Question

22. Find the area of a quadrilateral piece of ground
one of whose diagonals is 60 metres long and the
perpendiculars from the other two vertices are 38
and 22 metres respectively.
tions​

Answer 1

Answer:

We know that the area of a quadrilateral is equal to the product of one diagonal and half the sum of perpendiculars drawn on it from other two vertices.

⇒ Area of a quadrilateral =

2

1

×diagonal×(p

1

+p

2

)

where, p

1

and p

2

are two perpendiculars drawn from opposite vertices$$

Given, length of one diagonal is 60m and the perpendiculars from the other two vertices are 38m and 22m, respectively.

⟹ Area of the quadrilateral =

2

1

×60×(38+22)m

2

=1800m

2