Question

22 question....options are 4,3,2,1

Answer 1

a = b^x
b = c^y
c = a^z

Writing all in terms of a,

a = b^x

Now, b = c^y..Substitute!

a = (c^y)^x

Now, c = a^z...Substitute!

a = [(a^z)^y]^x
a = a^xyz
a^1 = a^xyz

So, on comparison -
xyz = 1


So, the answer is 1.

Answer 2

$\huge\tt{\bold{\underline{\underline{Question᎓}}}}$

To find value of xyz :-

$\huge\tt{\bold{\underline{\underline{Answer᎓}}}}$

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$= > a = {b}^{x}$

$= > b = {c}^{y}$

$= > c = {a}^{z}$

Write all in term of 'a'

$= > a = {b}^{x}$

$Now,B = {c}^{y} .....substitute$

$= > a = { ({(c)}^{y} )}^{x}$

$= > Now,C = {a}^{z} .....substitute$

$= > a = { { [({a}^{z} )}^{y}] }^{x}$

$= > a = {a}^{xyz}$

$= > {a}^{1} = {a}^{xyz}$

=>Compare coefficient of both sides with respect to'a'

$\bold{\red{= > xyz = 1}}$

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