Business Studies, asked by ninjagamer17, 9 months ago

22.
Which term of an arithmetic progression 2, 7, 12, 17, is 137

Answers

Answered by ShírIey
137

a = 2

Common difference= a2 - A1

=> 7 - 2

=> 5

d = 5

an = 137

By Using formula= an = a+(n -1)d

Putting Values:-

=> 137 = 2 + (n - 1) × 5

=> 137 -2 = (n - 1) × 5

=> 135 / 5 = (n - 1)

=> 37 = n -1

=> n = 1 + 37

=> n = 38

38th Term of an Arithmetic progression is 137

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Answered by Anonymous
16

Answer:

Hey mate hope it helps u.....

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