226. If the length of a rectangle is increased by 10%. By what percent its width will
be decreased so that area remains same?
(a) 10%
(b) 11%
ot
%
1019
(a):11
Answers
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Step-by-step explanation:
Increase in length by 10% or 1/10th ,will require 1/(10 + 1 ) or 9 1/11% decrease in width to kep area constant.
This is a rule worth remembering.
Alternate quick method :
Net percentage change if two variables are multiplied together is given by :
A + B + AB/100
Here, A= 10% , let B = -x, net change = 0
10 +(-x) + (10 * -x)/100 = 0
=> 10 - x - x/10 = 0
10 = 11x/10
X = 100/11 = 9 1/11%
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