Question

234.2gm sugar syrup contain 34.2 of sugar . what is the molarity of the solution

Answer 1

The molality = n of moles / mass of solvent in kg

The mass of solvent in kg = 0.2kg

So molality = 0.0999÷ 0.2= 0.495 m

The molarity = n/ v

= 0.0999÷ 0.2342= 0.422 mol/L

Hope the answer is useful