Chemistry, asked by komalsanu, 8 months ago

25. Which of the following is a square planar complex?
(1) [NICI4]2-
(2) [PtBr4]2-
(3) [ZnBr4]2-
(4) [Au(CN)]2-
plz explain it well...........​

Answers

Answered by TrickYwriTer
2

Correct Question :-

Which of the following is a square planar complex?

(1) [NICI4]²-

(2) [PtBr4]²-

(3) [ZnBr4]²-

(4) [Ni(CN)4]²- ✔

To Find :-

  • Which of the following complex has square planar structure ?

Explaination :-

Q1)

 \mathsf {[NiCl_{4}] {}^{2 - } }

Calculation of O.N. :-

→ x - 1×4 = -2

→ x = -2 + 4

→ x = 2

 \mathsf{Electronic \:  configuration \:  of \:  Ni } \\  \mathsf{</p><p>[Ar] 4s {}^{2} 3d {}^{8} }

Then,

 \mathsf{Electronic \:  configuration  \: of  \: Ni {}^{2 + }  } \\  \mathsf{[Ar] 3d {}^{8} }

Orbital diagram :-

( Refer to the attachment. )

Hence,

Hybridisation = sp³

Q2)

 \mathsf{[PtBr_{4}] {}^{2 - } }

Calculation of O.N. :-

→ x - 1×4 = -2

→ x = -2 + 4

→ x = 2

 \mathsf{Electronic  \:  configuration  \: of  \: Pt} \\ </p><p> \mathsf{[Xe]4f {}^{14}5d {}^{9} 6s {}^{1} }

Then,

 \mathsf{Electronic \:  configuration  \: of \:  Pt  {}^{2 + } } \\  \mathsf{[Xe] 4f {}^{14}  5d {}^{8} }

Orbital diagram :-

( Refer to the attachment. )

Hence,

Hybridisation = sp³

Q3)

 \mathsf{[ZnBr_{4}] {}^{2 - } }

Calculation of O.N. :-

→ x - 1×4 = -2

→ x = -2 + 4

→ x = 2

 \mathsf{Electronic \:  configuration \:  of  \: Zn} \\ </p><p> \mathsf{[Ar] 4s {}^{2}  3d {}^{10} }

Then,

 \mathsf{Electronic \:  configuration \:  of  \: Zn {}^{2 + } }</p><p> \\  \mathsf{[Ar]  3d {}^{10} }

Orbital diagram :-

( Refer to the attachment. )

Hence,

Hybridisation = sp³

Q4)

 \mathsf{[NiCN_{4}] {}^{2 - } }

Calculation of O.N. :-

→ x - 1×4 = -2

→ x = -2 + 4

→ x = 2

 \mathsf{Electronic \:  configuration  \: of \:  Ni}</p><p> \\  \mathsf{[Ar] 4s {}^{2}  3d {}^{8} }

Then,

 \mathsf{Electronic \:  configuration  \: of  \: Ni {}^{2 + } }</p><p> \\  \mathsf{[Ar] 3d {}^{8} }

Orbital diagram :-

( Refer to the attachment. )

Hence,

Hybridisation = dsp²

Therefore,

Option D is correct.

Note :-

  •  \mathsf{CN {}^{-}} is a strong field ligan and as it approaches the metal ion, the electron must pair up.
Attachments:
Answered by Anonymous
0

Answer:

hi kajal aman here , happy dusheera ladli,,

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