27 term of an ap is 9 term is -10 and common difference is 5 by 7
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Heya !
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Let a be first term and d be common differnece.
It is given that 9th term is -10 and d = 5/7.
So, a₉ = a + 8d
⇒ -10 = a + 8 X 5/7
⇒ -10 = a + 40/7
⇒ a = -70/7 - 40/7
⇒ a = -110/7
Hence, a = -110/7.
Now, we have to find a₂₉,
(using formula, aⁿ = a + (n-1)d)
a₂₉ = -110/7 + 28 X 5/7
a₂₉ = -110/7 + 20
a₂₉ = -110/7 + 140/7
a₂₉ = 30/7.
Hence, 29th term of given AP is 30/7.
Hope it helps
Refer to this link for same :- https://brainly.in/question/2084267
Ur answer is here.
Let a be first term and d be common differnece.
It is given that 9th term is -10 and d = 5/7.
So, a₉ = a + 8d
⇒ -10 = a + 8 X 5/7
⇒ -10 = a + 40/7
⇒ a = -70/7 - 40/7
⇒ a = -110/7
Hence, a = -110/7.
Now, we have to find a₂₉,
(using formula, aⁿ = a + (n-1)d)
a₂₉ = -110/7 + 28 X 5/7
a₂₉ = -110/7 + 20
a₂₉ = -110/7 + 140/7
a₂₉ = 30/7.
Hence, 29th term of given AP is 30/7.
Hope it helps
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