Math, asked by amit5742, 1 year ago


27. Two years ago a man was 6 times as old as his son. After 18 years he will be twice as old as his son.
what will be the presentage of the father and the son? 2 वर्ष पहले पिता की उस बेटे से 6 गुणा थी। अब से 18 साल
बाद पिता की उम्र बेटे की उम्र से दो गुनी होगी। पिता व पुत्र की वर्तमान आयु ज्ञात करो।​

Answers

Answered by taiwooladimeji100
1

Answer:

Step-by-step explanation:

let d father age represent m

let d son represent d

:

Write an equation for each statement, simplify as much as possible

:

Two years ago a man was six times as old as his son.

m- 2 = 6(d-2)

m - 2 = 6d - 12

m = 6d - 12 + 2

m = 6d - 10

:

In 18 years he will be twice as old as his son.

m + 18 = 2(d+18)

m + 18 = 2d + 36

m = 2d + 36 - 18

m = d + 18

From the 1st equation, replace m with (6d-10)

6d - 10 = 2d + 18

6d - 2d = 18 + 10

4d = 28

d = 28/4

d = 7 yrs is the son's age

Find Dad's age

m = 6(7) - 10

m = 42 - 10

m = 32 yrs is Dad's age

:

:

Check solutions in the statement:

"In 18 years he will be twice as old as his son."

32 + 18 = 2(7 + 18)

50 = 2(25)


amit5742: thank you
taiwooladimeji100: mark as brainliest please
amit5742: matlab
Similar questions