Question

28 ^ 2 into 15^3 into 25 ^ 2 by 7 ^ 5 into 10 ^ 8 into 6 ^3​

Answer 1

Answer:

Step-by-step explanation:

(28 ^ 2) x (15 ^ 3) x (25 ^ 2)

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(7 ^ 5) x (10 ^ 8) x (6 ^ 3)

convert to prime factors:

(7 x 2 x 2)^2 x (3 x 5)^3 x (5^2)^2       7^2 x 2^4 x 3^3 x 5^(3+4)

------------------------------------------------ =   -------------------------------------------        

(7^5) x (2 x 5)^8 x (2 x 3)^3                  7^5 x 2^8 x 5^8 x 2^3 x x3^3

= 7^(2-5) x 2^(4-8-3) x 3^(3-3) x 5^(7-8)

= 7^(-3) x 2^(-7) x 1 x 5^(-1)

=                    1

  -------------------------------

  7^3 x 2^7 x 5