Question

28 5 3 72
60 6 ? 114
48 7 4 128

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Answer 1

Answer:

The correct option is B .i.e., 2

Step-by-step explanation:

Logic :

Step 1- Add 1st no. with square of 2nd & 3rd no.

Step 2- Now Add first Digit of all 3 nos to sum of Step 1.

For Ist Row :

Step 1 = $28+5^2+3^2$ = 28 + 25 + 9 = 62

Step 2 = 62 + 2 + 5 + 3 (∵ 2nd & 3rd nos. are single digit)

           = 72

For IIIrd row :

Step 1 = $48+7^2+4^2$ = 48 + 49 + 16 = 113

step 2 = 113 + 4 + 7 + 4 = 128

For IInd row : say missing no is x.

Step 1 = $60+6^2+x^2=60+36+x^2=96+x^2$

Step 2 = $96+x^2+6+6+x = 114$

Now we solve this quadratic equation.

$x^2+x-6=0\\by\:quadratic\:formula, we\:get\\\\x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}\\\\x=\frac{-1 \pm \sqrt{1-4.1.(-6)}}{2.1}\\\\x=\frac{-1 \pm \sqrt{25}}{2}\\\\x=\frac{-1 \pm 5}{2}\\\\x=\frac{-1 + 5}{2}\:\: and \:\: x=\frac{-1 - 5}{2}\\\\x=\frac{4}{2}=2\:\:and\:\;x=\frac{-6}{2}=-3$  

So the Option B matches i.e., the missing value is 2.

Answer 2

Answer:

28 5 3 72

60 6 ? 114

48 7 4 128

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