Question

28. The sum of two numbers, as well as, the difference between their squares is 9. Find the
numbers. solve by qudratic equation​

Answer 1

$\huge\boxed{\fcolorbox{red}{yellow}{Shailesh}}$

Hey

Here is your answer,

Let one number be a and next number be b

We know that,

a+b= 9-------(1)

a²-b²= 9

As a²-b²= (a+b)(a-b)

So, (a+b)(a-b)= 9

But a+b= 9

(9)(a-b)= 9

a-b= 1-------(2)

Adding (1) and (2),

a+b+a-b= 9+1

2a= 10

a= 5

b= 9-5= 4

Hope it helps you!

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