Question

28g of nitrogen reacts with 6g of hydrogen completely as per the given equation to form ammonia. How much will be the mass of ammonia formed

Answer 1

The balanced equation for the reaction is: 3H2 (g) + N2 (g) -> 2NH3 ... 3mol H2 react with 1 mol N2 to produce 2 mol NH3 ... Mass of 8 mol NH3 = 8*17 = 136g NH3 produced. ... 6g of hydrogen will react with 28g of nitrogen to give 34g ofammonia.

Answer 2

Given: 28g of nitrogen reacts with 6g of hydrogen completely to form ammonia.

To find: We have to find the mass of ammonia formed.

Solution:

The reaction between nitrogen and hydrogen is given as-

$N_2+3H_2\rightarrow 2NH_3$

Thus one mole of nitrogen reacts with three moles of hydrogen gas to form two moles of ammonia.

The molecular weight of nitrogen is 28 grams.

The molecular weight of hydrogen gas is 2 grams.

The molecular weight of ammonia is 17 grams.

Thus 28 grams of nitrogen reacts with 6 grams of hydrogen gas to form 2×17=34 grams of ammonia.

So, 34 grams of ammonia is formed.