Question

29. A, B, C and D are four consecutive numbers. If the sum of A and D is 103 what is the product of B and C? [February 28, 2015 @ 42m 50s] 1) 2652 2) 2562 3) 2970 4) 2550 5) None of these

Answer 1

::::::::---let four numbers---::::::::


¶(x),(x+1),(x+2),(x+3)

given A+D is 103 I.e. 2x+3=103 and x=50


product of B and C is (x+1)×(x+2)


therefore 51×52=2652

option A is correct
please mark it brainliest answer.Please

Answer 2

Given:-

Sum of A and D = 103

To Find:-

The product of B and C.

Solution:-

We can easily calculate the product of B and C by using these simple steps.

As

Sum of A and D = 103

Since these are 4 consecutive numbers, so if

A = x

B = x+1

C = x+2

D = x+3

Here, the Sum of A and D = 103

$x + x + 3 = 103$

$2x + 3 = 103$

$2x = 103 - 3$

$2x = 100$

$x = \frac{100}{2}$

$x = 50$

So, A = 50

B = 51

C = 52

D = 53

Now we have to find the product of B and C

$p = b \times c$

$p = 51 \times 52$

$p = 2652$

Hence, The product of B and C is 2652, and Option 'A' is correct.

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