Question

29.
Evaluate :
sin 2x tan-(sin x) dx​

Answer 1

Answer:

(Pi/2)-1

Step-by-step explanation:

Answer 2

Step-by-step explanation:

Sin 2x tan (-sin x) = - sin2x tan (sin x)

- 2 sin x cos x sin (sinx) /Cos (sinx)

Cos (x+sinx) =cos x cos (sinx) - sin x sin (sinx)

Cos (x+sinx) - cos x cos (sinx) = - sin x sin (sinx)

2cosxCos (x+sinx) -cosx cos x cos (sinx) /cos (sinx)

$\frac{2 \cos \alpha \times \cos( \alpha + \sin( \alpha ) )} {\cos( \sin( \alpha ) ) } - { \cos( \alpha ) }^{2}$