Question

29. The rate of emission of energy per unit surface area of a blackbody is proportional to
power
of its absolute the temperature.
(a) 2nd
(b) 3rd
(c) 4th
(d) 5th​

Answer 1

Answer:

Rate of energy emission is directly proportional to 4  

th

 power the temperature of the body so  

E  

2

​  

 

E  

1

​  

 

​  

=  

T  

2

4

​  

 

T  

1

4

​  

 

​  

 

We have  

E  

2

​  

 

E  

1

​  

 

​  

=  

16

1

​  

 

So we have  

T  

2

​  

 

T  

1

​  

 

​  

=(  

16

1

​  

)  

1/4

=  

2

1

​  

 

so T  

2

​  

=2T  

1

​  

=2(127+273)K=800K

Or T  

2

​  

=800−273=527  

0

C

Option B is correct.

Explanation: