297. In an office, there are 2 teams- Mavericks with 10 members and Marauders with 15 members. 4 members of team Maverick and 6 members of team Marauders can finish a job in 10 days. 3 members of Maverick and 7 members of Marauders can finish the same job in 12 days. If both the teams work on the same job independently, which team will finish first and by how many days?
a. Mavericks, by 15 days
b. Mavericks, by 5 days
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c. Mavericks, by 20 days
d. Marauders, by 20 days
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Mavericks , by 20 days
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Answer: Mavericks, by 5 days
Step-by-step explanation:
let mavericks team efficiency is x and marauders team efficiency is y.
as 4 members of team Maverick and 6 members of team Marauders can finish a job in 10 days. members of Maverick and 7 members of Marauders can finish the same job in 12 days
so (4x + 6y) *1 0 = (3x+7y)*12
x = 6y
it is clear that mavericks efficiency is greater. so
mavericks whole team complete work in
(4x + 6y) *1 0 = 10x*d
4x+x=xd
5 =d
so mavericks will independently complete work in s days.
hence option (b) is correct.
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