Question

(√2a + √3b)²
please solve it​

Answer 1

Step-by-step explanation:

this is your answer of the question

Answer 2

• As per the data given in the question, we have to determine the value of the expression.

        Given data:- $(\sqrt{2a}+\sqrt{3b})^{2}.$

        To find the value of exxpression=?

• $(a+b)^{2}$  the formula is an algebraic identity. It is read as a plus b whole square.

• Here, we apply the algebra formula; $(a+b)^{2}=a^{2}+2ab+b^{2}.$

       $\Rightarrow( \sqrt{2}a+\sqrt{3}b)^{2}\\\Rightarrow (\sqrt{2}a)^{2}+2\times\sqrt{2}a\times \sqrt{3} b+(\sqrt{3}b)^{2}\\\Rightarrow 2a^{2}+2\sqrt{6}ab+3b^{2}.$

      Hence, the value will be $2a^{2}+2\sqrt{6}ab+3b^{2}.$