2a-b=9 ;a-b=3 this is simultaneous equation of 10th std please answers this
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2a-b=9 ;a-b=3
a-b=3 so 2*3=6≠9
a-b=3 so 2*3=6≠9
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Answered by
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2a - b = 9 ... eq(1)
a - b = 3 ... eq(2)
subtract (1)&(2), we get
a = 6
from (2)
6 - b =3 => b= 3
thus a= 6
& b=3
a - b = 3 ... eq(2)
subtract (1)&(2), we get
a = 6
from (2)
6 - b =3 => b= 3
thus a= 6
& b=3
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