Question

2cos2 90 + 4cos2 45 +tan2 60 + 3cosec2 60 + 1 / 3 sec 60 - 7/2 sec2 45 + 2 cosec 30 -1

Answer 1

Answer:

By applying trignometric values ,

-35/12 +√3

hope it helps u......

Answer 2

Answer:

By using trigonometric values, the expression becomes 2×0^2+4×(1/√2)^2+(√3)^2+3×(2/√3)^2+1/3.(2)-7/2(√2)^2+2.2-1

= 0+2+3+2+(2/3)-7+4-1

= 11/3