Math, asked by Jiteshsaini123, 9 months ago

2cos2b.cos(A-B)= cos(A+B)+cos(A-3b)

Answers

Answered by Bhumiraghav

Cos(A+B)cos(A−B)≡(cosAcosB−sinAsinB)(cosAcosB+sinAsinB)≡cos2Acos2B−sin2Asin2B≡cos2A(1−sin2B)−(1−cos2A)sin2B≡cos2A−cos2Asin2B−sin2B+cos2Asin2B≡cos2A−sin2B

Answered by avikajindallion

Answer:

Cos(A+B)cos(A−B)≡(cosAcosB−sinAsinB)(cosAcosB+sinAsinB)≡cos2Acos2B−sin2Asin2B≡cos2A(1−sin2B)−(1−cos2A)sin2B≡cos2A−cos2Asin2B−sin2B+cos2Asin2B≡cos2A−sin2B

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