2ltr mixture of Co and co2 is passed through red hot coke, vol increases to 1.4 times find out the percentage composition of the mixture
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Answered by
1
Answer:
NSWER
C+CO
2
→2CO
⇒ Initial volume =1L
Final volume =1.6L
Let V
CO
2
=x V
CO
=(1−x)
⇒(1−x)+2x=1.6
1+x=1.6
x=0.6
∴%CO
2
=60%, %CO=40%
Hence, solved.
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Answer:
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