Question

(2m - 1)x + 3y - 5 =0, 3x + (m - 1)y - 2 = 0

Answer 1

(2m-1)x = 5-3y
x = 5-3y/2m-1
3(5-3y) / 2m-1 + (m-1)y - 2 = 0
15 - 9y /2m - 1 + (m -1) - 2 =0
(15 - 9y) (m - 1) + (2m - 1) (m-1) = 2( 2m-1)
15m-15-9my +9y +2m2-2m-m+1=4m-2
12m-9my+9m+2m2-4m=-2-1+15
17m-9my+2m2=12
2m2-9my+17m=12