Question

2root5x^2-3x-root5=0

Answer 1

Answer:

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$2 \sqrt{5} {x}^{2} - 3x - \sqrt{5} \\ \\ 2 \sqrt{5} {x}^{2} - (5 - 2)x - 3 \\ \\ 2 \sqrt{5} {x}^{2} - 5x + 2x - \sqrt{5} \\ \\ \sqrt{5} x(2x - √5) + 1(2x -√5 ) \\ \\ (2x - √5) (\sqrt{5}x + 1) \\ \\ \\ \\ hope \: it \: helps \: u \\ \\ \\ \\ follow \: me$

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