Question

2s
$2 {sin}^{2} \binom{\pi}{6} + {cosc}^{2} + \binom{\pi}{6} {cos}^{2} \binom{\pi}{3} = \binom{3}{2}$

Answer 1

2sin^2(π/6)=2×(1/4)=1/2

cosec^2(π/6)=4

cos^2(π/3)=1/4


so... Answer is:(1/2)+4+(1/4)
=19/4