Question

what will be the area if the ba ce of angled triangle is 8cm and hypotenuseis 10m

Answer 1

By Pythagoras theorem we will find perpendicular
${p}^{2} + {b}^{2} = {h}^{2} \\ {p}^{2} + {8}^{2} = {10}^{2} \\ {p}^{2} + 64 = 100 \\ {p}^{2} = 100 - 64 \\ {p}^{2} = 36 \\ p = \sqrt{36} = 6$
perpendicular ie height =6cm
now area of the triangle
$\frac{1}{2} \times base \times height = area \\ \frac{1}{2} \times 6 \times 8 = area \\ area = 24 {m}^{2}$