Question

2sin²(22.5)= 1-1/√2
then what's the value of sin (22.5) ?
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Answer 1

Answer:

Given : 2$sin^{2}$(22.5) = 1 - 1/$\sqrt{2}$

• $sin^{2}$(22.5) = (1-1/$\sqrt{2}$)/2

                         = ($\sqrt{2}$ - 1)/2$\sqrt{2}$

Taking squire roots on both sides

       sin22.5     = ($\sqrt{2-\sqrt{2} }$)/2