2sin7A cos3A is equal to
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Hey
--> 2sin 7A cos 3A
= 2 sin [ 5A + 2A ] cos [ 5A - 2A ]
= sin 2( 5A ) + sin 2( 2A )
= sin 10A + sin 4A ✓✓
Hope this helps ^_^
--> 2sin 7A cos 3A
= 2 sin [ 5A + 2A ] cos [ 5A - 2A ]
= sin 2( 5A ) + sin 2( 2A )
= sin 10A + sin 4A ✓✓
Hope this helps ^_^
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