Question

2t-4=3/10(5t-3) solve the equation​

Answer 1

Answer:

$\longrightarrow\sf 2t-4=\dfrac {3}{10}(5t-3)$

$\longrightarrow\sf 2t-4=\dfrac {3 (5t-3)}{10}$

• Use cross multiplication

$\longrightarrow\sf 3 (5t-3)=10 (2t-4)$

$\longrightarrow\sf 15t-9=20t-40$.

$\longrightarrow\sf 15t-20t=-40+9$

$\longrightarrow\sf -5t=-31$

$\longrightarrow\sf 5t=31$

$\longrightarrow\bf t=\dfrac {31}{5}$

Answer 2

Step-by-step explanation:

Answer:

$\longrightarrow\sf 2t-4=\dfrac {3}{10}(5t-3)$

$\longrightarrow\sf 2t-4=\dfrac {3 (5t-3)}{10}$

• Use cross multiplication

$\longrightarrow\sf 3 (5t-3)=10 (2t-4)$

$\longrightarrow\sf 15t-9=20t-40$.

$\longrightarrow\sf 15t-20t=-40+9$

$\longrightarrow\sf -5t=-31$

$\longrightarrow\sf 5t=31$

$\longrightarrow\bf t=\dfrac {31}{5}$