2X^2-4√2+3=0 split the middle term
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2x² -4√2x +3 =0
2x² - 3√2 -1√2 +3=0
2x² - 3√2 -1√2 +3=0
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DEAR FRIEND ,
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2x²- 4√2x + 3 =0
2x²- 3√2x - √2x + 3 =0
√2x(√2x-3) - 1(√2x+3)=0
(√2x-3)(√2x-1)=0
So, √2x-3 =0 and √2x-1 = 0
x = 3/√2. or x = 1/√2
HOPE IT HELPS YOU
_________________
____________
HERE IS YOUR ANSWER
_______________________
_______________________
2x²- 4√2x + 3 =0
2x²- 3√2x - √2x + 3 =0
√2x(√2x-3) - 1(√2x+3)=0
(√2x-3)(√2x-1)=0
So, √2x-3 =0 and √2x-1 = 0
x = 3/√2. or x = 1/√2
HOPE IT HELPS YOU
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