Question

2x^2+bx+9=0 if the 1 root of equation is 1/2find the other root also find the value of b​

Answer 1

Answer:

The answer is in the picture

Answer 2

AnswEr :

Given Equation,

$\sf \: 2x {}^{2} + bx + 9 = 0$

• 1/2 is one of the root of the above equation

To finD : Value of b

Now,

Putting x = 1/2 in the above equation :

$\sf \: 2 \times { (\dfrac{1}{2} )}^{2} + \dfrac{b}{2} + 9 = 0 \\ \\ \longmapsto \: \sf \: \dfrac{b + 1}{2} = - 9 \\ \\ \longmapsto \: \sf \: b + 1 = - 18 \\ \\ \longmapsto \: \boxed{ \boxed { \sf b = - 19}}$

For x = ½,the value of b would be - 19

Thus,

The equation would be 2x² - 19x + 9 = 0