Math, asked by vimmydubey280779, 10 months ago

2x^2-under root 3x-3 factorise

Answers

Answered by mysticd
3

Answer:

 \red { Factors \:of \: 2x^{2} - \sqrt{3} x - 3}

 \green {= (x-\sqrt{3})(2x +1 )}

Step-by-step explanation:

 2x^{2} - \sqrt{3} x - 3

/* Splitting the middle term, we get

 = 2x^{2} -2\sqrt{3} x + \sqrt{3} x - \sqrt{3}\times \sqrt{3}

 = 2x(x- \sqrt{3} ) + \sqrt{3} (x-\sqrt{3})\\= (x-\sqrt{3})(2x +1 )

Therefore.,

 \red { Factors \:of \: 2x^{2} - \sqrt{3} x - 3}

 \green {= (x-\sqrt{3})(2x +1 )}

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