Question

2x^2+x+4=0 find the roots of quadratic equation by completing squaes

Answer 1

★ QUADRATIC EQUATIONS ★

Here, 2x² + x - 4= 0

So, 2x² + x = 4
⇒ x² + $\frac{x}{2}$ + $\frac{1}{4}$ = 2+ $\frac{1}{4}$
⇒ (x + $\frac{1}{2}$)² = $\frac{9}{4}$
⇒ (x + $\frac{1}{2}$) = ± $\frac{3}{2}$

∴ x = $\frac{3}{2}$ - $\frac{1}{2}$ = 1
             or
    x = $\frac{3}{2}$ + $\frac{1}{2}$ = 2

Thus, x = 1 or 2.

Answer 2

2x^2+x+4=0

a= 2, b=1, c=4

D=b^2-4ac

=1^2-4*2*4

=1-32

= -31

we know that if the value of D is negative so, the quadratic equation have not real roots