2x^2+x-4=0 find the ropts of the quaderatic equation
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x=-b+√D/2a
=-1+√33/4
one root is this
and another root is -1-√33/4.
=-1+√33/4
one root is this
and another root is -1-√33/4.
Ribhu11:
But D=+33
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Let the roots of the equation ax^2+bx+c=0 be d and e then
values of d and e are
d= [-b+(b^2 - 4ac)^1/2]/2a
e=[-b-(b^2 - 4ac)^1/2]/2a
So the roots of 2x^2+x-4=0 are
a=2, b=1 c=-4
d=[-1+(1+32)^1/2]/4=[-1+(33)^1/2]/4
similarly, e=[-1-(33)^1/2]/4
values of d and e are
d= [-b+(b^2 - 4ac)^1/2]/2a
e=[-b-(b^2 - 4ac)^1/2]/2a
So the roots of 2x^2+x-4=0 are
a=2, b=1 c=-4
d=[-1+(1+32)^1/2]/4=[-1+(33)^1/2]/4
similarly, e=[-1-(33)^1/2]/4
Hehe Its ok. It happens with me too at times.
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