2x-3/3x-1=2x+5/3x+1,Solve the given equation.
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cross multiplicarion snd sove the equation then..
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Solution :
(2x-3)/(3x-1) = (2x+5)/(3x+1)
Do the cross multiplication , we get
=> (2x-3)(3x+1)=(2x+5)(3x-1)
=> 2x(3x+1)-3(3x+1) = 2x(3x-1)+5(3x-1)
=> 6x²+2x-9x- 3 = 6x² - 2x+ 15x -5
=> 6x² -7x - 3 = 6x² + 13x - 5
=> 6x² - 7x - 6x² - 13x = -5 +3
=> - 20x = -2
=> x = (-2)/(-20)
=> x = 1/10
••••
(2x-3)/(3x-1) = (2x+5)/(3x+1)
Do the cross multiplication , we get
=> (2x-3)(3x+1)=(2x+5)(3x-1)
=> 2x(3x+1)-3(3x+1) = 2x(3x-1)+5(3x-1)
=> 6x²+2x-9x- 3 = 6x² - 2x+ 15x -5
=> 6x² -7x - 3 = 6x² + 13x - 5
=> 6x² - 7x - 6x² - 13x = -5 +3
=> - 20x = -2
=> x = (-2)/(-20)
=> x = 1/10
••••
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