Question

2x - 3y + 15, 13y + 12 Subtract the given expressions.

Answer 1

Given expressions,

2x - 3y + 15 and 13y + 12

Let the 2x - 3y + 15 be ex(i),

& 13y + 12 be ex(ii).

On Subtracting expression (ii) from ex(i).

2x - 3y + 15 - 13y - 12

= 2x - 16y + 3

Hence, the answer when the given expressions are subtracted is 2x - 16y + 3.

Hope it helps.

Answer 2

Hi ,

i ) Subtracting second expression

from first

2x - 3y + 15 - ( 13y + 12 )

= 2x - 3y + 15 - 13y - 12

= 2x - 3y - 13y + 15 - 12

= 2x - 16y + 3

ii ) Subtracting first expression

from second , we get

13y + 12 - ( 2x - 3y + 15 )

= 13y + 12 - 2x + 3y - 15

= -2x + 13y + 3y + 12 - 15

= -2x + 16y - 3

I hope this helps you.

: )