Math, asked by rahulpanjwani9504, 1 year ago

2x+3y=17,3x-2y=6 by substituting method

Answers

Answered by niboriyamayankpdu9da
15
2x+3y=17 ------ (1)
3x-2y= 6 ------(2)

1 equation in value of x
2x+3y=17
2x=17-3y
x= 17-3y/2 ----------'(3)

2 equation put in value of x
3x-2y=6
3(17-3y/2)-2y=6
51-9y/2-2y=6
51-9y-4y=6
-5y-4y=6-51
-9y= -45
9y=45
y= 45/9
y = 5

3 equation put in value of y
x=17-3y/2
x= 17-3(5)/2
x= 17-15/2
x= 2/2
x=1


x= 1 and y= 5



is answer
Answered by samuel1746
2

Answer:

Step-by-step explanation:

2x+3y=17 ------ (1)

3x-2y= 6 ------(2)

1 equation in value of x

2x+3y=17

2x=17-3y

x= 17-3y/2 ----------'(3)

2 equation put in value of x

3x-2y=6

3(17-3y/2)-2y=6

51-9y/2-2y=6

51-9y-4y=6

-5y-4y=6-51

-9y= -45

9y=45

y= 45/9

y = 5

3 equation put in value of y

x=17-3y/2

x= 17-3(5)/2

x= 17-15/2

x= 2/2

x=1

x= 1 and y= 5

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