2x+3y=18 and xy=5 find value of x and y
Answers
Answered by
1
xy = 5
x = 5/y
Substituting in 2x + 3y = 18
10/y + 3y = 18
10 + 3y² = 18y
3y² - 18y + 10 = 0
Here the roots are irrational. There seems to be some info missing.
If we change the question:
xy = 5
x = 5/y
Substituting in 2x + 3y = 17
10/y + 3y = 17
10 + 3y² = 17y
3y² - 17y + 10 = 0
3y² - 15y - 2y + 10 = 0
3y(y - 5) -2(y - 5) = 0
(y - 5)(3y - 2) = 0
y = 5 or 2/3
If y = 5 then x = 1
x = 5/y
Substituting in 2x + 3y = 18
10/y + 3y = 18
10 + 3y² = 18y
3y² - 18y + 10 = 0
Here the roots are irrational. There seems to be some info missing.
If we change the question:
xy = 5
x = 5/y
Substituting in 2x + 3y = 17
10/y + 3y = 17
10 + 3y² = 17y
3y² - 17y + 10 = 0
3y² - 15y - 2y + 10 = 0
3y(y - 5) -2(y - 5) = 0
(y - 5)(3y - 2) = 0
y = 5 or 2/3
If y = 5 then x = 1
Similar questions