Question

2x+3y=20 , 2x-y=4 solve by cramers rule method​

Answer 1

Answer:

Two numbers differ by 3. The sum of twice the smaller number and thrice the greater number is 19. Find the numbers.

ANSWER:

Let the smaller number be x and the larger number be y.

Given that the two numbers differ by 3 so,

y-x=3 .....(I)

Also, sum of twice the smaller number and thrice the greater number is 19

So, 2x+3y=19 ......(II)

The two equations obtained are

y-x=3

2x+3y=19

Multiplying (I) by 3 we get

3y-3x=9 .....(III)

Adding (III) and (II) we have

4y = 28

⇒y=

28

4

=7

Putting the value of y = 7 in (I) we get

7-x=3⇒-x=3-7⇒-x=-4⇒x=4

Thus, the two numbers are 4 and 7.

Step-by-step explanation:

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