Question

2x + 3y +4z=0, x+2y-5z=0, 10x +16y - 6z=0​

Answer 1

2x+3y+4z=0.......(1)

x+2y-5z=0...........(2)

10x+16y-6z=0.......(3)

2x+3y+4z=0

2x+4y-10z=0(multiplying ewn2 by2)

and subtracting from eqn1

-y+14z=0

y=14z

substitute y value in eqn1

2x+3(14z)+4z=0

2x+42z+4z=0

2x+46z=0........(4)

again substitute y value in eqn(

3)

10x+16(14z)-6z=0

10x+224z-6z=0

10x+218z=0......(5)

from eqn(4)and eqn (5)

we get z=0

from y=14z

we get y=0

by substituting these values in eqn (1) we get x=0

there fore

x=0

y=0

z=0

Hope this help u