Question

2x+3y=7 and 6x+5y=11 by substitution method​

Answer 1

Answer:

2x+3y =7 ..............(1)

6x+5y=11................(2):

(1)×2

4x+6y=14.............(3)

(2)-(3)

2x-y=-3

X=-3+y/2

X= -3+y/2 (1) mein

2(-3+y/2) + 3y =7

y=4

y=4 (2) mein

6x+5×4=11

X= -3/2

X= -3/2

y=4