2X + 3Y = 8 and 5X + 4Y = 13
Answers
Answered by
3
5x+4y=13 ------- eq1
2x+3y=8 -------- eq2
Let's Multiply the eq1 with 2 & eq2 with 5
eq1 => 10x+8y=26
eq2=> 10x+15y=40
on subtracting eq1 from eq2
we will get, 7y=14, =>y=2
on substituting the value of y in any of the eq. let's consider eq2, we will get, 2x+3×2=8=>2x=2=>x=1
Therefore, 1,2 is the system of above equations.
2x+3y=8 -------- eq2
Let's Multiply the eq1 with 2 & eq2 with 5
eq1 => 10x+8y=26
eq2=> 10x+15y=40
on subtracting eq1 from eq2
we will get, 7y=14, =>y=2
on substituting the value of y in any of the eq. let's consider eq2, we will get, 2x+3×2=8=>2x=2=>x=1
Therefore, 1,2 is the system of above equations.
sharan16:
X = 1 how find it
by substituting the value of y in any of the given equations we can find x. we get y=2, putting it on eq 2=> 2x+3×y=8, 2x+3×2=8=>2x+6=8=>2x=2=>x=1
yeah he correct
Similar questions