Question

2x^5-3x^4+2x-3 by x^2-1 the remainder in the form of px+q find p and q

Answer 1

Step-by-step explanation:

${x}^{2} - 1 = 0$

${x}^{2} = 1$

$x = 1$

$2 {x}^{5} - 3 {x}^{4} + 2x - 3$

$substitute \: \: x = 1 \: \: in \: \: the \: \: above \: \: \\ equation.$

$2 {(1)}^{5} - 3 {(1)}^{4} + 2(1) - 3$

$2 - 3 + 2 - 3$

$4 - 6$

$- 2$

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