Question

-2x+5y=19
3x-4y=-18

Answer 1

Given, two equations are :
$\qquad\qquad-2x+5y=19-----(1)\\\qquad\qquad3x-4y=-18-----(2)$
multiplying 3 with equation (1) and 2 with equation (2) and then adding both equations.

$3(-2x+5y=19)\\2(3x-4y=-18)$

-6x + 15y + 6x - 8y = 57 - 36

7y = 57 - 36 = 21

y = 3

put y = 3 in equation (1),

-2x + 5 × 3 = 19

-2x = 19 - 15 = 4

x = -4/2 = -2

hence, x = -2 and y = 3

Answer 2

Given, two equations are : 
\begin{lgathered}\qquad\qquad-2x+5y=19-----(1)\\\qquad\qquad3x-4y=-18-----(2)\end{lgathered}−2x+5y=19−−−−−(1)3x−4y=−18−−−−−(2)​ 
multiplying 3 with equation (1) and 2 with equation (2) and then adding both equations.

\begin{lgathered}3(-2x+5y=19)\\2(3x-4y=-18)\end{lgathered}3(−2x+5y=19)2(3x−4y=−18)​ 

-6x + 15y + 6x - 8y = 57 - 36 

7y = 57 - 36 = 21 

y = 3

put y = 3 in equation (1), 

-2x + 5 × 3 = 19

-2x = 19 - 15 = 4 

x = -4/2 = -2

hence, x = -2 and y = 3