2x < 100 and x is an integer, how many of the 2x + 2 integers will be divisible by 3 and by 2?
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26 = 64 and 27 = 128. If 2x /lt; 100, then the highest x is x = 6
Possible values for x: 0 , 1 , 2 , 3 , 4, , 5 , 6. 2x + 2 can take the values 3 , 4 , 6 , 10 , 18 , 34 , 66
Out of these values, only 6 , 18 and 66 are divisible by 3 and by 2.
I hope this will help you
Possible values for x: 0 , 1 , 2 , 3 , 4, , 5 , 6. 2x + 2 can take the values 3 , 4 , 6 , 10 , 18 , 34 , 66
Out of these values, only 6 , 18 and 66 are divisible by 3 and by 2.
I hope this will help you
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