Question

2x(x+1)+(x -3)(2 -x)-(x+2)(x+3)=0​

Answer 1

Answer:6

Step-by-step explanation:

2x^2+2x+2x-x^2-6+3x-(x^2+3x+2x+6)

=>x^2+7x-6-x^2-5x-6=0

=>7x-6-5x-6=0

=>2x-12=0

=>2x=12 => x=6

Answer 2

Solution:-

=> 2x(x+1)+(x -3)(2 -x)-(x+2)(x+3)=0

=>(2x²+2x)+(2x-x²-6+3x)-(x²+3x+2x+6) = 0

=>(2x²+2x)+(-x²+2x+3x-6)-(x²+3x+2+6) = 0

=>(2x²+2x) + (-x²+5x-6) - (x²+5x+6)

= 0

=> 2x² + 2x - x² + 5x - 6 - x²-5x-6 = 0

we can write it as

=> 2x²-x²-x² + 2x + 5x-5x -6-6 = 0

=> 2x² - 2x² + 2x - 12 = 0

=> 2x -12 = 0

=> 2x = 12

=> x = 12/2

=> x = 6

i hope it helps you.