(2x-y)^2-11 (2x-y)+28
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1
Answer:
refer to the attachment
Step-by-step explanation:
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5
Step-by-step explanation:
Let 2x -y = a
a^2 -11a+28=0
a^2 -7a-4a +28=0
a(a-7) -4(a-7)=0
(a-4)(a-7)=0
a=4 or a=7
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