Question

for equilibrium AB =A+B at given temperature, the pressure at which one-third of AB is dissociated is numerically equal to​

Answer 1

Given :

AB (g) ⇔ A(g) + B(g)

To find :

Pressure at which one third of AB is dissociated

Solution :

•                AB (g) ⇔       A(g)     +       B(g)

              t =0        a                  0                  0

              t = t₁      a-x                x                   x

•  Kp = (Pa × Pb) / Pab

               =  [xP/(a+x)]² / [(a-x)P/(a+x)]

               = x²P / (a²-x²)     [x/a = 1/3]

               P = 8Kp      

The pressure at one third of dissociation is 8Kp

Answer 2

Answer:

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