Question

2x+y=5,3x+2y=8 solve by multiplication method​

Answer 1

Given equations

$2x+y = 5\\3x+2y = 8$

Multiplying the first equation with 2 and the second equation with 1 we get,

$4x+2y = 10\\3x+2y = 8$

Solving, we get,

$4x+2y = 10\\\underline{ 3x + 2y = 8}\\\underline{\underline{x = 2}}}$

$\implies 4 + y = 5\\\implies y = 5-4\\\implies y = 1$

$\boxed{\boxed{\bold{Therefore, \ the \ values \ of \ x \ and \ y \ are \ 2 \ and \ 1 \ respectively.}}}}$

                                                     

Answer 2

Answer:

here is your answer dear

first take equation (i)

2x + y = 5

$2(2x + y = 5) \\ 4x + 2y = 10 \: \: \: \: (ii)\\ 3x + 2y = 8 \: \: \: \: \: \: \: (iii) \\ \\ \\subtract \: eq \: \: (ii) \: and \: (iii) \\ 4x + 2y = 10 \\ 3x + 2y = 8 \\ - \: \: \: \: - \: \: \: \: \: \: - \\ - - - - - - \\ x = 2 \\ so \: the \: value \: of \: y = 1$

hope it help you dear ✌️