Question

(2x-y-z)3 +(2y-z-x)3 +(2z-x-y)

Answer 1

It is wrong sorry

Multiple the 3 to everything in first bracket, then the second bracket multiple 3 and last nothing and last cancelation of common one u will get the answer last

Answer 2

Answer:

(2x- y- z)+(2y-z-x)+(2z-x-y)

=0

let, a=2x-y-z

b=2y-z-x

c=2z-x-y

since, a+b+c=0

hence, a^3+b^3+c^3=3abc

(2x-y-z)^3+(2y-z-x)^3+(2z-x-y)

=3(2x-y-z)(2y-z-x)(2z-x-y)

Step-by-step explanation:

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