Question

2x° , ( x°+30 ) , ( x°-10 )​

Answer 1

Answer:

80°, 70° , 20°

Step-by-step explanation:

sum of all angles of ∆ = 180°

2x° + ( x°+30 ) + ( x°-10 ) = 180°

4x° + 20° = 180°

4x° = 180°–20°

4x° = 160°

x° = 160°/4 = 40°

angle 1 = 2x° = 2× 40° = 80°

angle 2 = ( x°+30 ) = 40° + 30° = 70°

angle 3 = ( x°-10 ) = 30° – 10° = 20°

Answer 2

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Given Angles →

1. 2x°
2. ( x° + 30 )
3. ( x° - 10 )

Now , using Angle Sum Property...

2x + ( x + 30 ) + ( x - 10 ) = 180°

2x + x + 30 + x - 10 = 180°

4x + 20 = 180°

4x = 160°

x = 40°

So, Angles would be →

• 2x = 2×40 = 80°

• x + 30 = 40 + 30 = 70°

• x - 10 = 40 - 10 = 30°